(5x^(2/3))/3-(40x^(-1/3))/3=0

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Solution for (5x^(2/3))/3-(40x^(-1/3))/3=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x^(2/3))/3-((40*x^(-1/3))/3) = 0

(5*x^(2/3))/3+(-40/3)*x^(-1/3) = 0

5/3*x^(2/3)-40/3*x^(-1/3) = 0

t_1 = x^(1/3)

5/3*t_1^2-40/3*t_1^-1 = 0

(5/3*t_1^3-40/3*t_1^0)/(t_1^1) = 0 // * t_1^2

t_1^1*(5/3*t_1^3-40/3*t_1^0) = 0

t_1^1

(5/3)*t_1^3-40/3 = 0

(5/3)*t_1^3-40/3 = 0 // * 0

{ 1, -1, 2, -2, 4, -4, 5, -5, 8, -8, 10, -10, 20, -20, 40, -40 }

1

t_1 = 1

5*t_1^3-40 = -35

1

-1

t_1 = -1

5*t_1^3-40 = -45

-1

2

t_1 = 2

5*t_1^3-40 = 0

2

t_1-2

5*t_1^2+10*t_1+20

5*t_1^3-40

t_1-2

10*t_1^2-5*t_1^3

10*t_1^2-40

20*t_1-10*t_1^2

20*t_1-40

40-20*t_1

0

5*t_1^2+10*t_1+20 = 0

DELTA = 10^2-(4*5*20)

DELTA = -300

DELTA < 0

t_1 in { 2}

t_1 = 2

x^(1/3)-2 = 0

1*x^(1/3) = 2 // : 1

x^(1/3) = 2

x^(1/3) = 2 // ^ 3

x = 8

x = 8

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